Integrais definidas
Integrais definidas a Integrais definidas Gilson Würz. Licenciado em Física Instituto Federal de Educação Científica e Tecnológica Campus Jaraguá do Sul Math Calcule ∫ 2 x - 1 ( x - 2 ) ( x + 1 ) d x "> ∫ 2x - 1 ( x - 2 ) ( x + 1 ) dx ∫ 2 x - 1 ( x - 2 ) ( x + 1 ) d x Solução Expandindo f ( x ) = ( x - 2 ) ( x + 1 ) = x 2 - x - 2 → d f d x = 2 x - 1 "> f ( x ) = ( x - 2 ) ( x + 1 ) = x 2 - x - 2 → df dx = 2x - 1 f ( x ) = ( x - 2 ) ( x + 1 ) = x 2 - x - 2 → d f d x = 2 x - 1 ∫ 2 x - 1 ( x - 2 ) ( x + 1 ) d x = ∫ 1 f ( x ) d f ( x ) d x d x = ∫ d f ( x ) f ( x ) = ln f ( x ) + c = ln | ( x - 2 ) ( x + 1 ) | + c "> ∫ 2x - 1 ( x - 2 ) ( x + 1 ) dx = ∫ 1 f ( x ) df ( x ) dx dx = ∫ df ( x ) f ( x ) = ln f ( x ) + c = ln | ( x - 2 ) ( x + 1 ) | + c ∫ 2 x - 1 ( x - 2 ) ( x + 1 ) d x = ∫ 1 f ( x ) d f ( x ) d x d x = ∫ d f ( x ) f ( x ) = ln f ( x ) + c = ln | ( x - 2 ) ( x + 1 ) | + c Calcule ∫ 1 - x 2 x ( x 2 + 1 ) d x "> ∫ 1 - x 2 x ( x 2 + 1 ) dx ∫ 1 - x ...